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Does the below BLDC motor have the Peak Torque (20oz-in) at the rated speed?
Rated_Voltage: 24V
Rated_Speed: 4000RPM
Back_EMF_Constant: 3.7Vp/KRPM
Peak_Current: 4.4A
Rated_Current: 2.2A
Peak_Torque: 20oz-in
Rated_Torque: 10oz-in
Resistance: 1.5Ohms
Inductance: 2mH
Here is my calculation:
x = Rated_Speed * Back_EMF_Constant + Peak_Current * Resistance
If the above "x" exceeds Rated Voltage, then the motor can not exert Peak Torque(20oz-in) at the rated speed.
For the above motor:
21.4V = 4000RPM * 3.7Vp/KRPM + 4.4A * 1.5Ohms
Because 21.4v is less than Rated Voltage(24v), so it can exert the Peak Torque(short time) at the rated speed.
Is my calculation correct?
Thank you.
Rated_Voltage: 24V
Rated_Speed: 4000RPM
Back_EMF_Constant: 3.7Vp/KRPM
Peak_Current: 4.4A
Rated_Current: 2.2A
Peak_Torque: 20oz-in
Rated_Torque: 10oz-in
Resistance: 1.5Ohms
Inductance: 2mH
Here is my calculation:
x = Rated_Speed * Back_EMF_Constant + Peak_Current * Resistance
If the above "x" exceeds Rated Voltage, then the motor can not exert Peak Torque(20oz-in) at the rated speed.
For the above motor:
21.4V = 4000RPM * 3.7Vp/KRPM + 4.4A * 1.5Ohms
Because 21.4v is less than Rated Voltage(24v), so it can exert the Peak Torque(short time) at the rated speed.
Is my calculation correct?
Thank you.