J

hours of the day.

How is the power drawn by a 3-phase motor calculated ? Is the equation, 3^0.5 * V * A, correct and independent of the load on the motor ? Is it more accurate than using motor horse-power and efficiency to calculate power draw ? What formula do the electric utilities use for their load shedding calculations ?

Thanks in advance.

Jay Kirsch

Macro Automatics

2985 E. Hillcrest Drive, Ste 101

Thousand Oaks, CA 91362

[email protected]