AB SLC 100

K

Thread Starter

Keith

Need Programming manual or help writing simple program. Long time since I used this unit and lost manual.

Thanx.

Keith
 
I am unable to let you have our only copy of the SLC 100 manual but if you describe you requirements in detail I will help. Either with info from the manual or some suggestions for the code. if you wish contact me direct
[email protected]

ken
 
K

Keith Wourms

Hi Ken,
Thanx for reply and offer.
It is a simple on /off timer combined with a counter that I require.

When I "close" a contact (1 or 101) I wish to initiate a sequence where output 11 will be turned on for a determined time (~ 10 seconds) and then turned off for a determined time (likely the same value). This is to be considered one cycle and I would like to count (up or down) 500 cycles and then stop the process. A very handy feature would be a "pause" where if I closed the next contact (2 or 102) the timing and counter would pause until I opened the contact at which point it would resume. I was hoping the "count" could be displayed on my handheld programmer (1745-PT1)but it is not strictly necessary.

Thank you again
Keith Wourms
 
Keith
code as follows
rung 1 -| |- 001 -(L)- 701
rung 2 -|/|- 002 -| |- 701 -(RTO)- 901
PRE = 10.0
rung 3 -|/|- 002 -| |- 701 -| |- 901
-(RTO)- 902
PRE = 10.0
rung 4 -| |- 902 -(CTU)- 903
PRE = 500
rung 5 -| |- 902 -(RST)- 901
rung 6 -| |- 902 -(RST)- 902
rung 7 -| |- 903 -(U)- 701
rung 8 -| |- 903 -(RST)- 903
rung 9 -| |- 701 -|/|- 901 -( )- 011

rung 1 latches the state of input 1 (note the process will recycle after 500 counts unless I/P 1 is turned off or you add a one shot
rung 2 starts the first timer (set to 10 secs) unless I/P 2 is turned On
rung 3 runs the second timer
rung 4 counts the required cycles
rungs 5 and 6 reset the timers each cycle
rung 7 stops the operation at the end of 500 cycles
rung 8 resets the cycle count
rung 9 turns ON O/P 11 each cycle

I agree there are many newer (better?) devices available but assume you need to work with what you have.

Ken
 
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