X

From a literature that I found, one of the ways is to find out the accuracy for each individual instrument and the overall accuracy is equal to square root of the sum of squares of errors, e.g.:

a = sqrt (err1^2+err2^2+err3^2+...)

where a is the overall accuracy.

I believe this formula does not take account of the weighting of a certain error towards the overall error but instead it assumes that all errors have equal contribution for the total error.

Can we apply the same principle in this application or is there a better way of calculating this? Thank you.