Does anyone know the formula to calculate compressed air in an accumulator. If I have an accummulator that holds 45 cubic feet at atmospheric, then how much is that when compressed to 80 psig? Thanks JW
Assuming that T(1) = T(2), and V(1)=V(2) since the container is the same in both cases, the mass of the gas can be calculated from the following 2
equations:
P(1)*V=N(1)*R*T (1)
P(2)*V=N(2)*R*T (2)
It follows that N(2) is proportional to P(2)*N(1)/P(1)