K
Dear sir,
I would like to know my interpretation regarding the working of Flame scanner installed in GE Gas turbine with Mark VIe&es control system is correct or not.
Flame detector:
1. Sensor has two electrodes Anode in the center and cathode itself surrounded as wall and sensor is filled with inert gas.
2. Very high DC voltage around 330 volt will be across the anode and cathode electrodes.
3. Whenever the flame occurs on the combustion chamber the radiation strikes the sensor and the inert gas inside the sensor with electrodes creates or ionizes positively charged ions and electron pairs.
4. So that positive ions attracted to cathode and electrons to anode.(Electric field built s up)
5. Thus near the anode which gain sufficient energy can ionize additional gas molecules. (the region which is ionized with ions and electrons is called avalanche region).
6. Thus by above 5 th step the gas multiplication effect will take place with respect to the flame UV ray intensity.
7. So now the current conduction will occur through the medium of IONIZED INERT GAS.
8. Thus the current pulse rate will change accordingly with respective to flame intensity.
And at last i have question, and i want to know how the reading in the system is showing in HERTZ.
I would like to know my interpretation regarding the working of Flame scanner installed in GE Gas turbine with Mark VIe&es control system is correct or not.
Flame detector:
1. Sensor has two electrodes Anode in the center and cathode itself surrounded as wall and sensor is filled with inert gas.
2. Very high DC voltage around 330 volt will be across the anode and cathode electrodes.
3. Whenever the flame occurs on the combustion chamber the radiation strikes the sensor and the inert gas inside the sensor with electrodes creates or ionizes positively charged ions and electron pairs.
4. So that positive ions attracted to cathode and electrons to anode.(Electric field built s up)
5. Thus near the anode which gain sufficient energy can ionize additional gas molecules. (the region which is ionized with ions and electrons is called avalanche region).
6. Thus by above 5 th step the gas multiplication effect will take place with respect to the flame UV ray intensity.
7. So now the current conduction will occur through the medium of IONIZED INERT GAS.
8. Thus the current pulse rate will change accordingly with respective to flame intensity.
And at last i have question, and i want to know how the reading in the system is showing in HERTZ.