advertisement
from the E & I department...
Differential protection
Engineering and workplace issues. topic
Posted by speedtronic on 26 October, 2009 - 12:58 pm
In case of differential protection, say for generator, we know that current entering a phase must be equal to current leaving that phase. Now for example, there is a short cct between phase R & y at the point where current is entering the phase, just after CTs. So, now what will cause diff protection to operate? I mean due to short cct, will the current leaving these two phases will become zero? Which CTs will face maximum current, ones near the fault point or the others?
Will the current will flow in the reverse direction from the point where this short cct has happend? Please explain


Posted by Phil Corso on 27 October, 2009 - 9:57 am
Speedtronic, see:

http://control.com/thread/1026242938

Phil Corso


Posted by serpi1981 on 3 November, 2009 - 3:57 pm
I suppose you are talking about a two-phase short circuit. With a high impedance grounding in the generator (to reduce short circuit current in case of a phase to ground fault). The differential protection protects for two-phase and three-phase faults only.

The differential protection protect only against faults between the associated current transformers. The basic algorithm sums the vectors of the currents in such a way than the sum is zero when there is no fault inside the differential zone during normal operation. When a short cct occurs inside the differential zone the sum is different from 0 (there is a margin, the minimum pick up, for usual errors during normal operation). The contribution to the fault from the generator flows from the neutral side to the point where the fault is. And about the contribution of the electrical network it flows from the network to the faulty point. As the differential protection sums the currents it will trip in any case (with the contribution of both sides in different directions the sum is different of zero or with the contribution of just one side when the other side is disconnected(generator or network).

The maximum contribution to the fault usually is from the neutral side but the truth is it depends on the the venin equivalent circuit of the electrical network at the point of connection.

Tell me if I've forgot to answer something...


Posted by mitreviper on 1 December, 2009 - 1:57 am
Hi,

Why would one want to use differential protection? Would overload protection be sufficient against such faults?

In addition, if I have a Zero Sequence current transformer for detecting earth leakage, would this also protect against phase to phase fault? Please help.


Posted by Phil Corso on 1 December, 2009 - 2:38 pm
mitreviper...

1) Overload protection can't differentiate whether the fault is within the generator's zone of protection, or outside it!

2) No!

I suggest you use the Control.com Search feature. Their Archive contains numerous Protection topics!

Regards, Phil Corso

Your use of this site is subject to the terms and conditions set forth under Legal Notices and the Privacy Policy. Please read those terms and conditions carefully. Subject to the rights expressly reserved to others under Legal Notices, the content of this site and the compilation thereof is © 1999-2010 Nerds in Control, LLC. All rights reserved.

Users of this site are benefiting from open source technologies, including PHP, MySQL and Apache. Be happy.


Fortune
"What's the use of a good quotation if you can't change it?"
-- Dr. Who
Advertise here
Advertisement
our advertisers
Help keep our servers running...
Patronize our advertisers!
Visit our Post Archive