Resistor question

G

Thread Starter

Gr3mlin

Ok, i need some help. I have a 9volt power supply, that i need to drop down to 1.5v to run a IR-LED, they can anyone tell me what Resistor To use?
 
Y

Yeasir Rahul

You do not need to drop down the voltage. You actually need to limit the current. The LED will drop its rated voltage, if the current is limited by some means.

Use a simple 1k resistor in series with your IR-LED. The current throgh it would be approximately

(9 - 1.5)/1k = 7.5 mA

Visible LED ususally works well with currents in the order of 10 mA. I don't know about IR-LEDs, they should have same characteristics. If necessary reduce this resistance.

Cheers.

Yeasir Rahul
VoltSmith Technology
<a href="www.voltsmith.com">www.voltsmith.com</a>
 
No. No-one can tell you what resistor to use.

You haven't given enough information.

It's the current you have to worry about, anyway, not the voltage. 9 volt
power supply, the LED takes 1.5 volts, that leaves 7.5 volts for the
resistor.

Pick the resistor which will give the correct current at 7.5 volts.

Jiri
--
Jiri Baum <[email protected]> http://www.csse.monash.edu.au/~jirib
MAT LinuxPLC project --- http://mat.sf.net --- Machine Automation Tools
 
C

Curt Wuollet

That depends on the current needed. Most high intensity LEDs want about
50 ma.

R = E/I

9 V minus the 1.5 means about 7.5 across the resistor

7.5/.05 = 150 Ohms for a 50 ma LED
7.5/.02 = 375 Ohms for a 20 ma LED

Then you need to consider power ratings

P = I x E

1/2 watt resistors would do by inspection.
I'll leave the math as an exercise.

Regards
cww
 
R

Ramakrishnan, Raja \(GE Energy\)

Normally IR-LED takes current from 20 mA to 500 mA, checkup the current requirement and find out the value and power rating of resistor to meet your requirement. If you use 270 ohm, current flow limited to (7.5/270) 27.7 mA. It would require 1/4 (P=7.5 * 27.7 mA) Watt.
 
Without knowing the fwd current of the IR-LED, it would at best be hard to tell you what resistance to use. Also, I am surprised you can not use ohm's law to find the answeer for yourself, shame on the ones who responded and answered a very simple question any reasonable good technician should be able to figure out in under a minute (without a calculator). For yourself, go pickup a basic electronics book and learn how to use ohm's law and NO, I will not give you the answer, to be an engineer or technician you will have to put in some effort on your own. Would you give your kids the answers to their school work?

MJH
 
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