Search results

To anyone still interested... the September, 2011 issue of "Chemical Engineering" magazine contains a downloadable spreadsheet solution to "Calculate Liquid Volumes in Tanks with Dished Heads!" The authors are D. R. and R. B. Crookston. Regards, Phil Corso

Ranjan... I believe you missed the point of Gitesh's original question. He(?) asked if the delta-connected tertiary-winding provided a "balancing" function since it was not used to provide any protection/metering function. Subsequently, he noted it was connected to a voltage supervision...

Samiran Bairagya... do you mean stator end-turns, or rotor end-bells? Regards, Phil Corso

Mondula... sorry, correct thread is: http://control.com/thread/1273871432 Regards, Phil Corso

Prince... before replying to your second question, were you satisfied with the answer to your 1st question? Phil Corso

Abdul... Control.com Thread # 1026212105 contains a solution. Regards, Phil Corso <b>moderator's note:</b> full url is http://www.control.com/thread/1026212105. Please delete any spaces the forum software puts in the url.

Ambuj... I suggest you obtain a copy of the paper: "Dynamic Testing of Numerical Protection Relays" by Steve Turner, Senior Applications Engineer, Beckwith Electric Co.,Inc. One section details the Protection System you are interested in! Regards, Phil Corso (cepsicon[at]AOL[dot]com)

Prince... corrected to Irms formula:<pre> o Irms = Sqrt[ (Ir^2 + Is^2 + It^2)/3 ]</pre> Phil Corso

Prince... in answer to your 12-Sep-11 (00:16) an approximate (I emphasize 'approximate') formula, based upon the data you provided is: <pre> o kW = [Sqrt(3) x Vavg x Irms x Cos(phi)]/ 1,000, where, o Vavg = [( Vry + Vyb + Vbr)/3.0]. o Irms = [Sqrt (Ir^2 + Is^2 + It^2)/3] </pre> I...

Vas... your two readings should be measured relative to a common reference... for example, like neutral or earth! Regards, Phil Corso

Pmmeeranl... I suggest you search Control.Com archives for similar threads. Regards, Phil Corso

Prince... presuming you are interested in determining the overall power, please supply the following values: o R-Y Volts. o Y-B Volts. o B-R Volts. o R-Neutral Volts. o Y-Neutral Volts. o B-neutral Volts. o PF associated with Line Volts R-Y and R Amps. o PF associated...

Sensorless… it is: [email protected] Phil Phil

Sensorless... correction to my earlier post! Because you identified a relatively small capacitor, the motor you have is probably not a split-phase, capacitor-start, but a permanent split-phase, capacitor-run motor. If this is the case, please identify which type of motor you want analyzed...

Chris... the relatively small-size capacitor is indicative of a split-phase motor with a permanently connected "run-capacitor" and not a split-phase "capacitor-start" motor. Unless you are sure the motor winding has failed I suggest you test the capacitor. Regards, Phil Corso...

Senseless… first some basics. The capacitor-start motor is actually known as the Split-Phase Capacitor-Start motor. It has two electrical coils; one called the 'start-winding' or Ws, the other the 'run-winding' or Wr. They are physically displaced by 90 electrical degrees around the periphery...

Sensorless... if memory serves me, the theoretical equation you seek may be found in the Control.Com Archives. If your search is negative then let us know! Regards, Phil Corso

For those interested... the world's largest Grid-Scale Flywheel Storage system was commercially produced in Stephentown, N. Y. Last June, some 20MW was provided by Massachusetts-based Beacon Power to assist frequency-regulation service to the NYISO (New York Independent System Operator)...

But John, the OP specified a single heating-element! Regards, Phil Corso

Yogesh... I recommend you search the Control.Com Archive for like threads. You will find that most posters suggest grounding the shield at the panel-end, rather than the instrument-end, and never both-ends simultaneously! Regards, Phil Corso