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To those interested... upon the advice of a superior gender, following is the on-forum answer to the Electrical Puzzle! But first,
o I want to thank those men that contacted me off-forum for having the common courtesy to remove their cloak of anonymity.
o A caveat to PtPs... the answer contains formulas, so... Eyes-Closed, Ears-Covered, and Mouths Shut:
A) A 60Hz Sine-wave travels at the speed-of-light, or about 186,000 mph.
B) Using the formula for wavelength of a periodical sine-wave, λ = c/f, yields a wave-length, cycle-length, or period, equal to 186,000/60 or about 3,100 miles.
C) Since there are 360º per cycle, then a cycle-length or period, T, is equal to about 8.6 miles.
D) The distance around the loop, ignoring the 1/2 mile substation separation, is 100/8.6 or phi, Ø = about 11.6 deg!
E) Because the OVH lines on oposite side of the breaker are synchronized, and equal in magnitude, but not yet paralleled, there is voltage across the breaker-contacts.
F) Using the Law-of-Cosines, or more simply, the Isosceles-Rule when two sides have identical lengths, then the short side opposite the angle, phi, equals 2xSin(phi/2)x the length of one of the two identical sides!
G) The length of one of the two equal sides is equal to the OVH line’s phase-neutral voltage.
H) The short side is the voltage difference (rms) across each pole of the breaker contacts
I) Example: if the OVH line voltage is 173kV, then voltage across the contacts would be 0.2 x (173/sqrt[3]) or about 20kV.
So the answer to the original question is yes, close the breaker, but be ready for a great noise and flash! BTW, a greater difference requires greater thought!
If you need additional detail, don’t hesitate to contact me, on or off-forum! Regards, Phil Corso, [email protected]
o I want to thank those men that contacted me off-forum for having the common courtesy to remove their cloak of anonymity.
o A caveat to PtPs... the answer contains formulas, so... Eyes-Closed, Ears-Covered, and Mouths Shut:
A) A 60Hz Sine-wave travels at the speed-of-light, or about 186,000 mph.
B) Using the formula for wavelength of a periodical sine-wave, λ = c/f, yields a wave-length, cycle-length, or period, equal to 186,000/60 or about 3,100 miles.
C) Since there are 360º per cycle, then a cycle-length or period, T, is equal to about 8.6 miles.
D) The distance around the loop, ignoring the 1/2 mile substation separation, is 100/8.6 or phi, Ø = about 11.6 deg!
E) Because the OVH lines on oposite side of the breaker are synchronized, and equal in magnitude, but not yet paralleled, there is voltage across the breaker-contacts.
F) Using the Law-of-Cosines, or more simply, the Isosceles-Rule when two sides have identical lengths, then the short side opposite the angle, phi, equals 2xSin(phi/2)x the length of one of the two identical sides!
G) The length of one of the two equal sides is equal to the OVH line’s phase-neutral voltage.
H) The short side is the voltage difference (rms) across each pole of the breaker contacts
I) Example: if the OVH line voltage is 173kV, then voltage across the contacts would be 0.2 x (173/sqrt[3]) or about 20kV.
So the answer to the original question is yes, close the breaker, but be ready for a great noise and flash! BTW, a greater difference requires greater thought!
If you need additional detail, don’t hesitate to contact me, on or off-forum! Regards, Phil Corso, [email protected]
